Question

find points of intersection.
x^2 + y^2 = 25, 2x + y =10

Answer 1

x=3
y=4

Answer 2

dont care. i dont know how

Answer 3

\[x^2+y^2=25, y=10-2x\]
\[x^2+(10-2x)^2=25\]

Answer 4

and it = (5,0) too

Answer 5

Well its basically from the equation, a^2+b^2=c^2.
I remembered my special 3,4,5 Triangle and got the answer.

Answer 6

\[x^2+10^2-2(10)(2x)+(2x)^2=25\]
\[x^2+100-40x+4x^2-25=0\]
\[5x^2-40x+75=0\]

Answer 7

\[x^2-8x+15=0\]

Answer 8

\[(x-5)(x-3)=0=>x=5 or x=3\]

Answer 9

\[y=10-2x=> y=10-2(5)=10-10=0 or y=10-2(3)=10-6=4\]

Answer 10

so we have the ordered pairs where the curves/lines intersect are
(5,0) or (3,4)

Answer 11

abe gj on that thinking

Answer 12

i like that