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how do you find the domain and range of f(x) when f(x) is 3x-5? and when it's x^2-5?
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f(x)=y Just switch them then replace x and y.
there is no y in the function?
f(x)=y.
When f(x)=3x-5. The doman is x=5/3. When f(x)=x^2-5. The domain is x=squarerootof5.
When f(x)=x^2-5. The range is y>5
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When f(x)=3x-5. The range is all real numbers.
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