integral sin(1/x) dx ?
xsin(1/x) - Ci(1/x) + C
what on earth?
you can't integrate this thing. where did the question come from?
\[\int\limits 8x^2 \sin (1/10 x) dx\]
thats where the question came from
for the love of pete, wolfram doesn't give an answer! it gives the integral in terms of another integral.
\[8\int x^2\sin(\frac{1}{10}x)dx\] like that?
yes
so it is really \[\sin(\frac{x}{10})\] not \[\sin(\frac{1}{10x})\]
hahahahahah sorry
integrate by parts twice. pain in the butt, but if you want to use wolfram and follow the steps at least you will get a real answer this time
ok thanks
here you can look at this. but the basic idea is to integrate sin and differen tiate x^2. then you will have to do it once more http://www.wolframalpha.com/input/?i=integral+x^2sin%28x%2F%2810%29%29
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