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't' is proportional to the square root of 'd'. if t=12, d=4. a. Find a formula for 't' in terms of 'd' . b. Calculate the value of 't' when 'd' =9 ! :) if you answer it, u r my god....
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\[\Huge t = k \sqrt{d}\]
\[12 = k \sqrt{4} \to 12 = k \times 2 \to k =\frac{12}{2} \to k = 6\]
\[t = 6\sqrt{d}\]
a) \[\huge d = \frac{t^2}{36}\]
i think u can solve b.
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thnks dude! :)|dw:1314503646375:dw|
welks Suvi. =)
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