Eight cubes,each with an edge of length one inch,are positioned together to create a large cube. What is the difference in the surface area of the large cube and the sum of the surface areas of the small cubes?
A) 24 in^2
B) 16 in^2
C) 12 in^2
D) 8 in^2
E) 0 in^2

Question

Eight cubes,each with an edge of length one inch,are positioned together to create a large cube. What is the difference in the surface area of the large cube and the sum of the surface areas of the small cubes?
A) 24 in^2
B) 16 in^2
C) 12 in^2
D) 8 in^2
E)  0  in^2

anonymous · Answer

A cube itself has 6 sides, each with surface area of 1 (L x W which are each 1)
So each cube has an area of 6 in^2.
8 cubes, so 48 in^2

In the mega-cube, each cube only shows 3 of its sides. Therefore, each cube only has 3 in^2 represented. 8 cubes, 3x8 =- 24.

48 - 24 = 24 in^2

anonymous · Answer

so, A

jim_thompson5910 · Answer

Surface area of large cube = 6*2^2 = 24 square inches

Surface area of small cube = 6*1^2 = 6 square inches

Sum of small cubes surface area = 6*8  = 48 square inches


-----------------

So the difference is 48 - 24 = 24 square inches

So the answer is A

anonymous · Answer

ty

anonymous · Answer

small cube = area ?
large cube= area?

anonymous · Answer

The surface area of each small cube is 6 in^2. There is 8 of them. So that's 48 in ^2.

anonymous · Answer

Large cube area surface = 24
small is 6

anonymous · Answer

Surface area of large is 24 in^2

jim_thompson5910 · Answer

the surface area of the large cube is 24 square inches

the surface of one small cube is 6 square inches

anonymous · Answer

ok, I get now,ty

anonymous · Answer

A