sorry i cant get it right on here but i'm looking for the domain:
f(x2) x+2 over x^3-3x^2-4x12

domain is{x|x not equal sign______________}

Question

sorry i cant get it right on here but i'm looking for the domain:
f(x2)  x+2 over x^3-3x^2-4x12

domain is{x|x not equal sign______________}

anonymous · Answer

Is this it?$$f(x ^{2})=\left(\begin{matrix}x+2 \ x ^{3}-3x ^{2}-4*12\end{matrix}\right)$$

anonymous · Answer

almost. hi dryanni...sorry it looks confusing but it's like this:
f(x)=  x+2
        ________________
         x^3-3x^2-4x+12

anonymous · Answer

there it goes again..lol....that line is suppossed to be the "over" sign

f(x)= x+2 (these would be the numerator) over  sign and then the denominator would be x^3-3x^2-4x+12

anonymous · Answer

Both the numerator and the denominator are defined for the entire domain of x. The equation is not defined (≠) when $$x^3-3x^2-4x+12$$is equal to 0, because you cannot divide by 0.
This is therefore a root problem for a polynomial of the third degree.

mimi_x3 · Answer

lols , next time just do "/" for over xD

anonymous · Answer

oh goodness...i was looking for the right sign....dumbcow showed me another sign before too...very helpful. i'll get it right next time.

anonymous · Answer

okay let me try it again

f(x)  x+2 / x^3-3x^2-4x+12

domain: {x|x and not equal sign then the answer ___________}