sorry i cant get it right on here but i'm looking for the domain: f(x2) x+2 over x^3-3x^2-4x12 domain is{x|x not equal sign______________}

Is this it?\[f(x ^{2})=\left(\begin{matrix}x+2 \\ x ^{3}-3x ^{2}-4*12\end{matrix}\right)\]

almost. hi dryanni...sorry it looks confusing but it's like this: f(x)= x+2 ________________ x^3-3x^2-4x+12

there it goes again..lol....that line is suppossed to be the "over" sign f(x)= x+2 (these would be the numerator) over sign and then the denominator would be x^3-3x^2-4x+12

Both the numerator and the denominator are defined for the entire domain of x. The equation is not defined (≠) when \[x^3-3x^2-4x+12\]is equal to 0, because you cannot divide by 0. This is therefore a root problem for a polynomial of the third degree.

lols , next time just do "/" for over xD

oh goodness...i was looking for the right sign....dumbcow showed me another sign before too...very helpful. i'll get it right next time.

okay let me try it again f(x) x+2 / x^3-3x^2-4x+12 domain: {x|x and not equal sign then the answer ___________}

Join our real-time social learning platform and learn together with your friends!