Question

OK here is a stumper...
Solve for b: 5b^2-5b+1=0

Answer 1

Solve for b: \[5b ^{2}-5b+1\]

Answer 2

\[5+\sqrt{5}/10, 5-\sqrt{5}/10\]

Answer 3

1+sqrt(5)/2 0r 1-sqrt(5)/2

Answer 4

by using quadratic formula
\[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
where a=5,b=-5 and c=1

plug the values into the formula
\[\frac{-(-5)\pm \sqrt{(-5)^2-4(5)(1)}}{2(5)}\]
\[\frac{5\pm \sqrt{25-20}}{10}\]
\[\frac{5\pm \sqrt{5}}{10}\]
\[\frac{5+\sqrt{5}}{10},\frac{5-\sqrt{5}}{10}\]

Answer 5

But the simplified answer is what I gave

Answer 6

yep that was it!!!! thanks