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Mathematics 21 Online
OpenStudy (anonymous):

show all work in simplifying 20x^2-93x+34/4x^2-9x-34. use complete sentences to explain your process.

OpenStudy (anonymous):

ok see here , ur answer is following

OpenStudy (anonymous):

20x^(2)-93x+(34)/(4)*x^(2)-9x-34 Reduce the expression (34)/(4) by removing a factor of 2 from the numerator and denominator. 20x^(2)-93x+(17)/(2)*x^(2)-9x-34 Multiply (17)/(2) by x^(2) to get (17x^(2))/(2). 20x^(2)-93x+(17x^(2))/(2)-9x-34 Since -93x and -9x are like terms, subtract 9x from -93x to get -102x. 20x^(2)-102x+(17x^(2))/(2)-34 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 2. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 20x^(2)*(2)/(2)+(17x^(2))/(2)-102x-34 Complete the multiplication to produce a denominator of 2 in each expression. (40x^(2))/(2)+(17x^(2))/(2)-102x-34 Combine the numerators of all expressions that have common denominators. (40x^(2)+17x^(2))/(2)-102x-34 Combine all like terms in the numerator. (57x^(2))/(2)-102x-34

OpenStudy (anonymous):

when dealing with these from kinds of problems you have to try and factor as much as possible. For instance then numerator factors to: (4x-17)(5x-2) and the denominator factors to: (x+2)(4x-17) which means you actually have: (4x-17)(5x-2) ------------- (x+2)(4x-17) now, the (4x-17) divides out and you are left with your answer of : (5x-2) ----- (x+2)

OpenStudy (anonymous):

@kush what is all that?

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