Question

The perimeter of a rectangle is 208 inches . The length exceeds the width by 28 inches . Find the length and the width

Answer 1

\[l=w+28\] and
\[2l+2w=208\] so
\[l+w=104\] replace l by w+28 get
\[w+28+w=108\]
\[2w+28=104\]
\[2w=76\]
\[w=38\]

Answer 2

width is 38, length is 38+28=66

Answer 3

how did you get 104?

Answer 4

oh i had
\[2l+2w=208\] because the perimeter is twice the length plus twice the width. then to make life simpler i divided everything by 2

Answer 5

oh Okay thank you !!!

Answer 6

yw