Question

p^8-q^8

Answer 1

factor?

Answer 2

yes

Answer 3

\[(p^4-q^4)(p^4+q^4)\]
\[(p^2-q^2)(p^2+q^2)(p^4+q^4)\]
\[(p-q)(p+q)(p^2+q^2)(p^4+q^4)\]

Answer 4

that is factor as the difference of two squares three times

Answer 5

p^8 - q^8 = (p^4)^2 -(q^4)^2
Apply difference of squares
p^8-q^8 = (p^4 +q^4)(p^4 -q^4)
Apply same formula twice

p^8-q^8 = (p^4 +q+4)(p^2 +q^2) (p+q)(p-q)

Answer 6

thanks!