How do you get the antiderivated of e^(2x). I'm having a massive smelly brain fart.
derivative* (I can't even spell)
lol ... or just multiply by 2/2
hint: let u = 2x, so du = 2dx ----> dx = du/2 So now you need to integrate e^(u)(du/2)
\[\frac{1}{2}\int 2e^{2x}dx\]
what i do is think of where e^2x would have come from: well, e^2x of course, then derive it and adjust. [e^2x]' = 2 e^2x ; so we have to divide off a two to get our answer
that is so much work. you know that it will look like \[?e^{2x}\] because the input will never change. so just think "what would i differentiate to get \[e^{2x}\] and you should come up with \[\frac{1}{2}e^{2x}\] by dint of reasoning
any of this make any sense?
I get the u-substitution version. Thanks guys
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