Turner’s treadmill starts with a velocity of
−2.7 m/s and speeds up at regular intervals
during a half-hour workout.After 33 min, the
treadmill has a velocity of −7.1 m/s.
What is the average acceleration of the
treadmill during this period?
Answer in units of m/s

Question

anonymous · Answer

Because it is not a constant acceleration, but an average. Then we can start by using the average velocity and divide that by the total time sample.$$[Velocity(final)-Velocity(initial)]/time$$there is a catch, time sample is in MINUTES, convert it to seconds before plug it into the equation. If you crunch the data, you'll learn to repeat the procedure.

anonymous · Answer

Ahh, they ask for acceleration in m/s ????? Your acceleration will be in Meters/second square (m/s^2)

anonymous · Answer

0.02222222 is this the answer?

anonymous · Answer

0.0022222222m/s^2

anonymous · Answer

2.22x10^-3

anonymous · Answer

(7.1m/s - 2.7m/s)/(33min X 60sec/min)