Question

solve for x

(3x+1)/(x-5)=0

this is as far as i got from the original problem...

Answer 1

3x+1=0
x=-1/3

Answer 2

(3x+1)/(x-5)=0 only when (3x+1)=0
3x=-1
x=-1/3
also x should b different from 5

Answer 3

Well in order for a fraction to be 0, the numerator must be 0, so just solve:
3x + 1 = 0
3x = -1
x = -1/3

Answer 4

but what happened to the denominator?

Answer 5

It doesn't matter what the denominator is, because you just want the numerator to be 0.

Answer 6

multiply (x-5) for both sides so we can get rid of fractions

Answer 7

ok, i see.

thanks to all of you :)

Answer 8

3x+1=x-5
2x=-4
x=-2

Answer 9

asma nooo, il x-5 btroo7 ma3 il zero

Answer 10

I didn't get wht Asma did O.o why did u equal tht?

Answer 11

ahhhh sa777 nseeet 3ashan minzaman ma 3imilto 3 months without school lol!

Answer 12

hehe its ok xP

Answer 13

lol

Answer 14

sorry i did something wrong i just wanted to cancel the denominator and it is right bbut at the right side it have to be zero so sorry again

Answer 15

ahhaaa....it's ok :D:D

Answer 16

if P(x)/Q(X) = 0 <===> P(x) =0 , we solve only for the numerator

Answer 17

=>3x+1=0 =>x=-1/3