*physics question(constant acceleration)*At a stoplight, a truck traveling at 15 m/s passes a car as it starts from rest.?
wrong board and where is the rest of the question?
At a stoplight, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s^2. How much time does the car take to catch up to the truck?
well, you just have two equations to set equal to one another
d=v*t+1/2*a*t^2 is the general form of these equations i believe
so 15*t=1/2*3*t^2
so 10*t=t^2
wait
therefore, t=10 or 0 and since 0 is when we start, t=10
how did you get 15? i know its right but i dont know how to get there
the truck is traveling at 15 m/s, so its distance equation is d=15*t
the car is starting from rest (v=0) and accelerating at 3m/s. so its distance equation is d=1/2*3*t^2
i just set those two equal to one another and solved
oh i see thanks, a lot i know this isnt the right place to ask questions but more people are here
lol, kk
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