Question

Find the arc length of the graph, on the interval [1/2,2], of
y=((x^3)/(6))+((1)/(2x))

Answer 1

Hi.
the arc length is generally :
L=integral[(1+y')^(1/2)]

Answer 2

sorry i could not use symboles

Answer 3

i still need help

Answer 4

1+y'=1+(1/2)x^2+ (1/2) lnx

Answer 5

and we should integral in our interval

Answer 6

\[\int\limits_{a}^{b}\sqrt{1+\left(\frac{dy}{dx}\right)^2}dx\]

Answer 7

i mean 33/16

Answer 8

Um, shomething not right there...

Answer 9

can you help me with this problem?

Answer 10

\[\int\limits_{1/2}^{2}\sqrt{1+\left(\frac{d(x^3/6+1/(2x))}{dx}\right)^2}dx\]

\[=\int\limits_{1/2}^{2}\frac{x^4+1}{2x^2}dx\]

Answer 11

\[=\frac{33}{16}\]

Answer 12

thanks