Question

last one!!
given the function: g(x)=4^(1-x)
find g(-1)

Answer 1

g(x)=4^(1-x)


g(-1)=4^(1-(-1)) ... replace EVERY x with -1


g(-1)=4^(1+1)


g(-1)=4^2


g(-1)=16

Answer 2

put
\[x=4^{1-y}\] solve for y

Answer 3

oh you're looking for the inverse?

Answer 4

@jim i am going to bet that this means
\[g^{-1}(x)\]

Answer 5

satellite likes to do his own thing

Answer 6

hell if i know! lol, this stuff isn't my cup of tea. it ust said simplify with integer or fraction

Answer 7

hmm sounds like simple function evaluation to me

Answer 8

can you draw it?

Answer 9

g(-1)=_____?

Answer 10

get
\[\log_4(x)=1-y\]
\[y=1-\log_4(x)\]
\[g^{-1}(x)=1-\log_4(x)\] good luck with no more math !!!

Answer 11

then again if it is
\[g(-1)\] then ignore me and use jim's answer

Answer 12

g(-1)=_____?

Answer 13

LOL.

Answer 14

or can you post a screenshot?

Answer 15

g(-1)=_____?

Answer 16

I THINK YOU'RE ANSWER WAS RIGHT, JIM....16.
THANK YOU BOTH!!!