Question

graph the equation using the slope and y intercept
y= -5/3x-4

Answer 1

The y-int is (0,-4). The slope may be used this way: as you move from the y-int 3 units in the positive (Right) x direction, you would then move 5 units down t= i the y-direction to get the point (0+3,-4-5) ==> (3,-9). You could also do this: when you move in the negative x-direction 3 units, you would then move 5 units up in the y-direction: (0-3,-4+5) ==> (-3,1). You could use any two of these three points to graph the line.

Answer 2

i lost you what about the slope?

Answer 3

Give me a minute, I'm graphing it for you to help make it clear

Answer 4

k

Answer 5

See attached

Answer 6

Take a look. The slope is m=-5/3 or it can be thought of as m=5/-3.

Answer 7

To go from the point (0,-4) to (3,-9), I am thinking of the slope the first way, that is, with the delta y (rise) as negative and the delta x (run) as positive.

Answer 8

To go from the point (0,-4) to (-3,1), I am thinking of the slope the second way, that is, with the delta y (rise) as positve and the delta x (run) as negative.

Answer 9

From any point (x,y) on the graph of a line you can use the slope to get another point using\[(x+\Delta x,y+\Delta y)\]