Evaluate the following integral: 1/([e^-x] +2) dx
I know I need to multiply by a special of (e^x/e^x) but from there I get shakey
multiply top and bottom by e^x then let u=1+2e^x
\[\int\limits_{}^{}\frac{e^x}{1+2e^x} dx\]
\[u=1+2e^x=>du=2e^x dx =>\frac{1}{2}du=e^x dx\]
really? i am impressed
\[\int\limits_{}^{}\frac{1}{2} \frac{du}{u}\]
learn something new every day!
\[\frac{1}{2} \ln|u|+C=\frac{1}{2}\ln(1+2e^x) +C\]
I messed up on my u. Ahhhhh. That's what happened.
Thanks for the clearly defined steps, I really appreciated it. : )
np
is this section on hyperbolic trig functions?
it seems some cal classes do not cover hyperbolic trig functions
I just been taught hyperbolic trig this semester. You're right though t semester I took Calc 2, it wasn't taught.
*last
i guess it depends on the instructor. my instructor do not cover it either.
but you sort of don't need to cover it i think
its just using algebra tricks
especially since they are usually covered in a 'here's the definition, and here are a couple properties" fashion
I like hyperbolic trig functions. If you're familiarwith your basic integration techniques then it's not too bad.
The 1st time I took Calc2 it was presented as "here's the definition" and then bam expected to know how to do them. It sucked.
myininaya can you help me with this: http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e6432dd0b8b1f45b4aefab4
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