Question

prove the statement using the epsilon, delta definition of a limit. limit x to a of c=c

Answer 1

let delta=d
let epsilon =e
so let's think
f(x)=c
L=c
so
|f(x)-L|<e
|c-c|<e
|0|<e
0<e
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it doesn't matter what we choose delta to be here
choose d= ? .so whenever 0<|x-a|<d, then
|f(x)-L|=|c-c|=0d=0?=0<e

Answer 2

what about lim of x to 1 to (2+4x)/3=2

Would that be the same format? f(x)= (2+4x)/3 and L=2