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OpenStudy (anonymous):
can someone show me how to do each steps on problem I attached?
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OpenStudy (anonymous):
OpenStudy (amistre64):
910... +-18
OpenStudy (amistre64):
A = pi r^2
r = sqrt(A/pi)
r = sqrt((910 +- 18)/pi)
OpenStudy (anonymous):
does sqrt mean square root? Also on the numerator are you adding 910 plus negative 18 all under pi?
OpenStudy (amistre64):
yes sqrt means square root
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OpenStudy (amistre64):
plus or minus
OpenStudy (anonymous):
oops! I mean't adding 910 to negative 18 which will all be over pi?
OpenStudy (amistre64):
over: (910 + 18)/pi
exact: (910)/pi
under: (910 - 18)/pi
OpenStudy (amistre64):
if i did it right, i get a variance of .1675..
OpenStudy (anonymous):
so you have to add first and then subtract?
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OpenStudy (amistre64):
|dw:1315361078317:dw|
OpenStudy (amistre64):
you are given an error that can be +18 or -18 either way
OpenStudy (amistre64):
so you have to determine the exact radius for the exact area; then determine the radiuses for the over and under allowances
OpenStudy (amistre64):
the difference in radiuses is then the margin of control
OpenStudy (anonymous):
so you solve for exact radius then over and under? How did you get .1675
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OpenStudy (amistre64):
by taking the difference in the radiuses;
OpenStudy (amistre64):
you might have to double it to fit the question tho since that is the variance from exact either way
OpenStudy (amistre64):
|dw:1315361391314:dw|
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