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find the length of the curve: x=3y^(4/3)-3/32y^(2/3), -64<=y<=64; find L.
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L= integral -64 to 64 (sqrt(1-f'(y)^2) dy
yes. i am having trouble finding the solution. i got the derivative as 4y^(2/3)-1/16y^(-1/3)
shouldn't the derivative be 4y^(1/3)-1/16y^(-1/3)
yes it should
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