Ask
your own question, for FREE!
Mathematics
17 Online
OpenStudy (anonymous):
how do you find the recursive formula for 200.00, 216.00, 233.28, 251.94? please explain
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
it looks moenyical
OpenStudy (amistre64):
moneyical
OpenStudy (amistre64):
maybe its interest?
OpenStudy (amistre64):
looks to be compounded
OpenStudy (anonymous):
.....what? i dunno if this helps but i think its supposed to be a shifted sequence...
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
251.94 = 200(1+r)^4
A/P = (1+r)^t
trt(A/P)-1 = r
id try for kicks:
(251.94/200)^(1/4) -1 = r
or about 5.94% maybe?
OpenStudy (anonymous):
...so is it just geometric?
OpenStudy (amistre64):
i think its almost geometric; i still think its some form of compunded interest
OpenStudy (anonymous):
oh...ok....thanks!
OpenStudy (amistre64):
(216/200)-1 = .08 for the first year
(233.28/216)-1 = .0799999 for the next one
(251.94/233.28)-1 = .07999 for the last set
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
A = 200(1.08)^t
OpenStudy (amistre64):
just about ....
OpenStudy (anonymous):
ok! thanks!!!! haha....
OpenStudy (amistre64):
i must be tired, that works fine
OpenStudy (anonymous):
haha im tired too....*sigh* just got back home and now i have to finish like all my homework
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
good luck with it :)
OpenStudy (anonymous):
thanks again!
OpenStudy (phi):
to make a recursion you world write
f(0)= 200
f(n+1)= f(n)*1.08
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!