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Solve the integral: sin^3(x) * cos^5(x) Which trigonometric rule(s) do you use and how?
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from looking at this i might actually lop off one of the sine's
maybe write it like this: sin^2(x)cos^5(x)sin(x), then i am sure you can use the Pythagorean identity
Substitute \(t = \sin^2x\) \[dx = \frac{dt}{2\sin x \cos x}\]
\[\int \frac{t* \cancel{\cos x * \sin x } (\cos^2 x)^2}{2 \cancel{\sin x * \cos x}}dt\]
\[\int \frac{t ( 1 - t)^2}{2}dt\]
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\[\frac{1}{2}* ( \int (t^3 + t - 2t^2)dt)\]
simpler is always better :) unless you need the practice
Indeed :)
there are many ways to skin a cat
;) Thanks
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