Question

Solve
x^2 +3x-4=0

Answer 1

\[0 = (x +4)(x-1)\]\[x=-4 and x= 1\]

Answer 2

(x+4)(x-1)=0

x = -4,1

Answer 3

\[x^{2}+3x-4=0\]
Factor it.
\[(x-1)(x+4)=0\]
\[x=1, x=-4\]

Answer 4

x^2+3x-4
since a=1 b=3 c=-4
x^2+(a+b)x+(ab)=(x+a)(x+b)
so you pick A and B which make those coefficients true
-1+4=3 check
(-1)(4)=-4 check so you can choose your A and B
A=-1
B=4 so therefore
(x-1)(x+4)=0
so x=1 and x=-4

Answer 5

disreguard the a=1 b=3 c=-4 does not have any sig in this explaination sorry