Question

Veolcity of 11 m/s
height in meters t seconds is given by y = 11t - 1.86t^2
how do i find avg velocity for interval [1,2]

Answer 1

Average Distance /Time.

Answer 2

could you show an example...ive tried using the equation but my numbers are not coming out correct

Answer 3

Just put t=1 and 2 to get the distance in 1 one second.

Answer 4

ok...heres what i tried...11(2) - 1.86(1)^2 all over 2-1 ..and i get some number that isnt right...am i using the equation incorrectly?

Answer 5

No, Get the height at 1 second, then at 2 seconds...

Answer 6

ok

Answer 7

so are you saying plug in 1 and 2 to the equation y= 11t -1.86t^2

Answer 8

when i plugged 1 in, i got 9.14; 2 i got 14.56 ..is that what you meant

Answer 9

Right, so....?

Answer 10

uhmm...would i then use: 14.56t - 9.14t^2 all over 2-1? ...or no

Answer 11

and plug the 2 and 1 in to the "t" on the top as well

Answer 12

when i plugged 1 in, i got 9.14; 2 i got 14.56

So what does this mean?

Answer 13

i plugged in 1&2 to the equation (11t - 1.86t^2)

Answer 14

to get 9.14 and 14.56

Answer 15

That's what u did, I asked u what does it mean?

Answer 16

haha oh sorry

Answer 17

im not sure...a little lost now haha, i have these numbers but im not sure why

Answer 18

U plugged in 1 and 2,

1 and 2 what?

Answer 19

seconds? ah..i dunno ha sorry

Answer 20

Right, so what does the formula actually calculate..?

Answer 21

the average velocity

Answer 22

..i think haha

Answer 23

Your questions says

"height in meters t seconds is given by y = 11t - 1.86t^2"

Answer 24

So what was the height at 1 sec?
2 sec?

Answer 25

so would i just do the 14.56 - 9.14?

Answer 26

Finally.....

Answer 27

haha sorry...was over thinking a little i guess, thanks for your help though i appreciate it

Answer 28

urwelcome