Question

Solve the following using quadratic equations: x^2+ 6x + 3 = 0

Answer 1

Would you like the quadratic formula or just the answer?

Answer 2

Just answer'

Answer 3

x = sqrt(6) - 3, x = -3-sqrt(6)

Answer 4

x^(2)+6x+3=0

Use the quadratic formula to find the solutions. In this case, the values are a=1, b=6, and c=3.
x=(-b\~(b^(2)-4ac))/(2a) where ax^(2)+bx+c=0

Substitute in the values of a=1, b=6, and c=3.
x=(-6\~((6)^(2)-4(1)(3)))/(2(1))

Simplify the section inside the radical.
x=(-6\2~(6))/(2(1))

Simplify the denominator of the quadratic formula.
x=(-6\2~(6))/(2)

First, solve the + portion of \.
x=(-6+2~(6))/(2)

Simplify the expression to solve for the + portion of the \.
x=-3+~(6)

Next, solve the - portion of \.
x=(-6-2~(6))/(2)

Simplify the expression to solve for the - portion of the \.
x=-3-~(6)

The final answer is the combination of both solutions.
\[x=-3+\sqrt6,-3-\sqrt6\]
~ means sqrt