Question

LOOK AT ATTACHMENT!!!

Answer 1

OK!!!
\[x + \frac{3}{2} = \frac{3}{4}(x+\frac{1}{2})\]
Expand RHS:
\[x + \frac{3}{2} = \frac{3}{4}x + \frac{3}{8}\]
\[x - \frac{3}{4}x = \frac{3}{8} - \frac{3}{2}\]
\[\frac{1}{4}x = \frac{3-12}{8}\]
\[x = -\frac{9}{2}\]

Answer 2

(2x+3)/2 = 3(x+1/2)/4
4(2x+3) = 2(3(x+1/2))
8x+12 = 2(3x+3/2)
8x+12 = 6x+3
8x-6x = 3-12
2x=-9
x=-9/2