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Mathematics 8 Online
OpenStudy (anonymous):

2cos^2x+3cosx-2=0

OpenStudy (anonymous):

Its like a polynomial. cosx=x so it'll be like 2x^2+3x-2=0

OpenStudy (anonymous):

is that factorable? with the plus in the middle how can you have a negative constant term.

OpenStudy (anonymous):

\[(2x-1)(x+2)\]

OpenStudy (anonymous):

which makes your life easy because you do not have to solve \[\cos(x)=-2\] because it cannot be, so only solve \[\cos(x)=\frac{1}{2}\]

OpenStudy (anonymous):

thanks! you rock.

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