Question

Point charge 3.5 uC is located at x = 0, y = 0.30 , point charge -3.5 uC is located at x = 0 y = -0.30 . What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge = 4.5 uC at x = 0.40 , y = 0?

Answer 1

3.5 uC = 3.5 x 10^(-6) C

Answer 2

so you have a positive point charge on top, negative on bottom, and positive to the right.

Answer 3

F1 = (9x10^9) * |(3.5 x 10 ^(-6))(4.5 x 10^(-6))| / (.5)^2
use this for
Fx = (answer above) * .4/.5
&
Fy = (answer above) * .3/.5

Answer 4

the value for the bottom will be the same except signs will change.

Fx for the bottom will be = negative ... (the answer above)
Fy for the bottom will be = the same as the answer above

Answer 5

er sorry... up 2 posts. ((( Fy = (answer above) * .3/.5 )))) add a negative to this answer because the force will pull Q down

Answer 6

add the 2 Fx's and add the 2 Fy's

The Fx's will cancel out and the answer will be 0 N
Fy will be 2 x whatever you got for Fy = (answer above) * .3/.5 <<< dont forget to add a negative

Answer 7

if you want a quick and dirty answer.... do

-2 x (9x10^9) * |(3.5 x 10 ^(-6))(4.5 x 10^(-6))| / (.5)^2 * .3/.5

Answer 8

put that in your calculator... it's the answer

except... mastering physics is gay and it's asking for the absolute value of the force

Answer 9

so the answer it is looking for is


2 x (9x10^9) * |(3.5 x 10 ^(-6))(4.5 x 10^(-6))| / (.5)^2 * .3/.5