How to solve for x:

y=(x-2) (x+2) (x^2+2)
Derived from: -x^4 + 2x^2 + y +8 = 0

Question

How to solve for x:

y=(x-2) (x+2) (x^2+2)
Derived from: -x^4 + 2x^2 + y +8 = 0

anonymous · Answer

Well if y=0, then one of the factors must equal zero too. Taking in all possibilities, we have $$x-2=0 \text{ so } x=2$$$$x+2=0 \text{ so } x=-2$$$$x^2+2=0 \text{ has no real solutions}$$Therefore$$x=\left\{-2,2\right\}$$For more solutions to textbook problems, be sure to check out http://www.slader.com/s/eWFrZXlnbGVl . I submit a lot of content there as well.

anonymous · Answer

you have given only 1 equation but there is 2 unknown quantity are there x and y so x can be find in terms of y only and i want to ask from yakeyglee why we will take y as 0