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Mathematics 18 Online
OpenStudy (anonymous):

help me here

OpenStudy (nilankshi):

what is the qus

OpenStudy (anonymous):

yeahh???

OpenStudy (anonymous):

biology lagi kah?

OpenStudy (nilankshi):

?????????????

OpenStudy (anonymous):

\[(1/2)^{\log_{3}\log_{1/5}(x^2 - 4/5)} > 1\] then \[\left| x \right| \in\]

OpenStudy (anonymous):

This is the question.

OpenStudy (anonymous):

log 3 or log ^3 kush

OpenStudy (anonymous):

it is log base 3

OpenStudy (anonymous):

@ Nilakshi where is the answer ?

OpenStudy (anonymous):

thats not the final

OpenStudy (anonymous):

then ??

OpenStudy (anonymous):

CMIIW kushwa

OpenStudy (anonymous):

\[(\log(1/2)\log_a{\log_{1/5}(x^2-4/5)}>\log 1\] \[\log_a{\log_{1/5}(x^2-4/5)}>0\] \[\log_{1/5}{(x^2-4/5)}<a^0\] \[x^2-4/5<(1/5)^1\] \[x^2<1\] Hence x is between -1 and 1, or \[x\in (-1,1)\]

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