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2x + 1 < 1 OR x + 5 > 8
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2x + 1 < 1 OR x + 5 > 8 2x < 1 - 1 OR x > 8 - 5 2x < 0 OR x > 3 x < 0/2 OR x > 3 x < 0 OR x > 3
how did you do that? you switched the signs?
which step?
2nd
the signs are the same as the first step
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no?
I'm dealing with each inequality individually
I solved 2x + 1 < 1 to get x < 0
separately, I solved x + 5 > 8 to get x > 3
but if you do it to one side dont you do it to the others?
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that's what I'm doing when I did 2x < 1-1, I subtracted 1 from both sides (first inequality only)
oh.
going from 2x + 1 < 1 to 2x < 1-1, the sign does not change
thanks
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