Question

find the equation of the circle which has the tangent lines x=-4, x=8, y=-2 and y=10

Answer 1

All you need is the radius and the center

The radius is equal to half the diameter. The diameter is equal to the distance from either x=-4 to x=8 or the distance from y =-2 to y=10


The center will be the midpoint between each tangent line (since the tangents are at right angles to one another). So simply find the midpoint that has an x coordinate that lies exactly halfway between x=-4 and x=8 and that has a y coordinate that lies halfway between y = -2 and y=10

Answer 2

(x-2)^2 +(y-4)^2 = 9

Answer 3

should be (x-2)^2 +(y-4)^2 = 36 since the radius is actually 6 (not 3) and the diameter is 12 (not 6)

Answer 4

here's what it should look like