Question

In this solution where did the 10 come from?

Answer 1

they plugged in the 5 into x+5 since x->5

Answer 2

so we had the last step before the 10 is 5+5

Answer 3

oh yeah, see, i don't see the little stuff haha

Answer 4

y-f(a)=f ' (a)(x-a) is the a in this equation the 5 in x ==>5?

Answer 5

same thing you was helping me with earlier I think y-25=10(x-5) or slope/intercept form y=10x-25

Answer 6

basically the relationship here is me finding the equivalent tangent line for the equation

Answer 7

so you are trying to find the tangent line at x=5
so it looks like f(x)=x^2
and we found f'(5)=10

so to find the tangent line
we use
y=f'(5)x+b

y=10x+b

we know a point on the line (5,5^2)=(5,25)

so

25=10(5)+b
25 =50+b
25-50=b
-25=b

so we have the equation of tangent line at (5,5^2) is
y=10x-25

Answer 8

wow, that just all made sense. first time this week.

Answer 9

lol

Answer 10

thanks again, im just going through the chapter working examples trying to understand them, im gonna go ahead and work the next few...lol