Question

the perimeter of a rectangle is 106m the length is 5m more thatn twice the width.what would be the demensions

Answer 1

2l+2w=106
2w=l+5

Answer 2

2l+2w=106
-l+2w=5

Answer 3

"length is 5 more than twice the width" shouldn't that be L=2W+5

Answer 4

yes my bad

Answer 5

it is very late here also

Answer 6

anyways
2l+2w=106
l-2w=5

Answer 7

3l = 111

Answer 8

2(x+5) + 2x = 106

4x = 96

x = 24 ----> width

x+5 = 299 --> length

Answer 9

299 can not be a length

Answer 10

oopps, its 29,

Answer 11

your second statement becomes false with those answers

Answer 12

2w+5 does not equal 29

Answer 13

l=37
w=16

Answer 14

dhashni is right i believe... i got 37 for one before i had to chime in

Answer 15

you forgot a 2

in your case it should have been

2(2x+5)+2x= 106

Answer 16

@nikki, here is the correct solution

2L+2W=106
L=2W+5

Subst L from equ 2 into equ 1
2(2W+5)+2W=106
4W+10+2W=106
6W=96
W=16
Now sub 16 into W in equ 2
L=2(16)+5=32+5=37

Length=37; width=16