Question

anyone who can help me for lagarithms on skype?

Answer 1

sure, but i'll have to add you, right?

Answer 2

and can you help me on my problem?

Answer 3

which one?

Answer 4

http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e76011c0b8b7d4f6cfe17ed

Answer 5

so, now i can help!

Answer 6

just tell me how.

Answer 7

can u help me here?

Answer 8

suree :)

Answer 9

3logx(2) + logx (18) =2

Answer 10

okay. so x = 12.

Answer 11

oh yeah but how?

Answer 12

see, x is the base, right??? then using log rules, 3log (base) x 2 is the same as log (base) x 2^3 = log (base) x 8.

Answer 13

then using log rules again, when the bases are the same, when you add them, the numbers get multiplied. so log (base) x (8*18) =

Answer 14

sorry, log (base) x (8*18) = 2.

so log (base) x 144 = 2.

so x^2 = 144.

so x = 12.

simple!

Answer 15

ok it was really simple =P

Answer 16

hahahaha, lol

Answer 17

i was trying to say that i have problem in add maths so i need help if any body can help me on skype....and by the way what r u saying =P

Answer 18

what is your username?, or e-mail id?

Answer 19

my skype name is andromeda.gaby

Answer 20

okayy, sent. check it out.

Answer 21

added you