Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

CAN SOMEONE HELP ME WITH THIS WORD PROBLEM PLEASE< ITS CONFUSING ME:( Andrew factored the expression -4x^3+2x^2+8x as -2x(4x^2-2x-8) . But when Melissa applied the distributive law and multiplied out -2x(4x^2-2x-8), she got -8x^3+4x^2+16x ; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state.

OpenStudy (anonymous):

if anyone here is good with word problems please help!:(

OpenStudy (anonymous):

explain if possible but if not thats fine with me I just want this word problem solved and I do need to know how to do it

OpenStudy (anonymous):

andrews factors are wrong

OpenStudy (anonymous):

umm

OpenStudy (anonymous):

I just need help solving it please, its driving me crazy

OpenStudy (anonymous):

-4x^3+2x^2+8x = 2x(x - 2x^2 +4)

OpenStudy (anonymous):

oooops, i mean when he factor out the -2x he only devided the equation by -x and forgot the 2, he must also devide it by 2 to get the correct factors.

OpenStudy (anonymous):

can you work it for me please:)

OpenStudy (anonymous):

-4x^3+2x^2+8x ----> so our factor is -2x devide every numberby -2x -2x(2x^2-x-4)

OpenStudy (anonymous):

so thats the answer?

OpenStudy (anonymous):

yup, :-)

OpenStudy (anonymous):

I thought the answer was -2x^2-4?

OpenStudy (anonymous):

oh so the answer is -2x(2x^2-x-4)?

OpenStudy (anonymous):

no, the right answer is -2x(2x^2-x-4), trust me, :-)

OpenStudy (anonymous):

oh my gosh thank you, you are a life saver I'm not joking:):):)

OpenStudy (anonymous):

hahaha, thank you, and your welcome! :-)

OpenStudy (anonymous):

no thank you:-)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!