Question

Find k so that the roots kx^2-6x+3=0 are equal?

Answer 1

(sqrt(k)x - sqrt(3))(sqrt(k)x - sqrt(3)) = 0
2(sqrt(k))(sqrt(3)) = 6
sqrt(k)sqrt(3) = 3
k = 3

here's the graph with the single root: http://bit.ly/qXZffP

Answer 2

k=0

Answer 3

which one is correct?

Answer 4

mine.

Answer 5

sqrt?

Answer 6

square root.

Answer 7

\[(\sqrt{k}x-\sqrt{3})(\sqrt{k}x-\sqrt{3})\]

Answer 8

multiplied out is \[kx^2 -2\sqrt{k}\sqrt{3}x+3\]
so \[2\sqrt{k}\sqrt{3} = 6\]\[\sqrt{k}\sqrt{3}=3\]\[\sqrt{k}=\sqrt{3}\]\[k=3\]