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If the series is convergent, find its sum: (n from 1 to infinity) ((n+1)/5^(n+1) -n/5^n )
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\[\sum_{n=1}^{\infty}\left( (n+1)/(5^{n+1}) -(n/5^{n}) \right)\] Just to clarify
/:)
Any ideas? I can't get anywhere near the answer.
THE SUME CONVEGES WHEN R IS r,<i1/5 since both sums aore geometruic hence the sume conveges at r<ii r<1/5. using the formulae |dw:1316452582049:dw|
but its not a geometric series?
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I haven't touched this material in a couple of decades - so a bit rusty :) Here's what wolf says about it - just need to see how to get there ... http://www.wolframalpha.com/input/?i=sum%28n%3D1%2Cinfty%2C%28n%2B1%29%2F5^%28n%2B1%29-n%2F5^n%29
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