Find the value of constants c and d that make the function below continuous at
x = 2.
x^2-3x x

Question

Find the value of constants c and d that make the function below continuous at 
x = 2.
            x^2-3x   x<2
F(x)      c              x=2

anonymous · Answer

whoops...and d+x  x>2 is the last part

anonymous · Answer

For it to be continuous, the values of each function would have to be equal at 2. In mathematical terms:
$$x^2-3x = c = d+x$$

anonymous · Answer

so like x^2-3x=d+x=2?

anonymous · Answer

They don't equal 2 I'm afraid. Take the first expression for example:
$f(x) = x^2-3x$
What would f(x) equal at x=2?

anonymous · Answer

no it would at 3 though?

anonymous · Answer

I mean what is f(2)?

anonymous · Answer

-2?

anonymous · Answer

Correct! Now going back to the equation I wrote earlier:
$$x^2-3x = c = d+x \text{       ;        } x=2$$You should be able to work out the values of c and d.