Question

[(x-3)+y]^2 help!!!

Answer 1

(x-3)² +2*(x-3)*y +y²=
x²-6x+9+2*(x-3)*y +y²

Answer 2

= 9-6 x-6 y+x^2+2 x y+y^2

Answer 3

(-3+x+y)^2
= (-3+x+y) (-3+x+y)
= -3 (-3+x+y)+x (-3+x+y)+y (-3+x+y)
= -3 (-3+x+y)+x (-3)+x x+x y+y (-3)+y x+y y
= -3 (-3+x+y)-3 x+x x+x y-3 y+x y+y y
= -3 (-3+x+y)-3 x+x x+2 x y-3 y+y y
= -3 (-3)-3 x-3 y-3 x+x x+2 x y-3 y+y y
= -3 (-3)+2 (-3) x+2 (-3) y+x x+2 x y+y y
= -3 (-3)-3 2 x-3 2 y+x x+2 x y+y y
= (-3)^(1+1)-3 2 x-3 2 y+x^(1+1)+2 x y+y^(1+1)
= 9-3 2 x-3 2 y+x^2+2 x y+y^2
= 9-6 x-6 y+x^2+2 x y+y^2

Answer 4

\[[(x-3)^2+y]^2=((x-3)^2)^2+2(x-3)^2(y)+y^2\]

Answer 5

wow. you could start with
\[(a+b)^2=a^2+2ab+b^2\] and put
\[a=(x-3),b=y\] so get as a first step
\[(x-3)^2+2(x-3)y+y^2\]

Answer 6

lol

Answer 7

might make life easier. then oh hi!

Answer 8

it's all yours

Answer 9

oops i misread too

Answer 10

oh so i will finish it

Answer 11

oh well what i said wasn't false

Answer 12

thank u all

Answer 13

looks good satellite

Answer 14

dont need the 6xy its 2xy

Answer 15

except coeffieicient of xy is 2

Answer 16

thanks. no one wants to square three terms at one time and do nine multiplications. at least i don't

Answer 17

\[x^2-6x+9+2xy-6y+y^2\]