Is the following problem simplified correctly? (5x+7)(5x-7)=25x2+70x-49
no. (a+b)(a-b) = a^2 - b^2. there is no ab term.
@bdboy, same as before... when you have the product of a sum and difference of binomials you have a factored form of a difference of two squares, that is, the product is a difference of two squares (se the right side of dhatraditya's formula?)
in your problem a=5x and b=7
yes, (a+b)(a-b) = a^2 +ba -ab - b^2 = a^2 +ab-ab-b^2 = a^2-b^2
when you have the product of a sum and difference of binomials, the middle two terms of the FOIL will always cancel each other out
thanks a ton i really appreciate you not just giving me the answers but actually explaing how to get them which helps me understand it so much more...
you need to multiply 25 and 2 then subtract 49
ok, what's the product
do you want me to show you
it think i totally just screwed it up.. somehow i got 1 but thats not correct
please that would be most helpful
that is the correct answer for zac's question
once you realize you have a difference of squares you just write\[(5x-7)(5x+7)=(5x)^2-7^2=25x^2-49\]with practice you would most likely do the middle step as a mental calculation
notice on the foil how the middle two terms cancel out\[(5x-7)(5x+7)=25x^2+35x-35x+49=25x^2-49\]
if I may, with mandolino's permission, \[(a+b)(a-b) = a(a-b) + b(a-b) = a^2 -ab + ba -b^2\] \[= a^2 - ab + ab -b^2 = a^2 - b^2\]
note that i just noticed a sign error in my previous post: the +49 in the middle step should be -49; the final answer is correct
@dhatraditya, i've just been playing off your posts
:)
bdboy try this one: (2x-3)(2x+3)
i'm going to give the answer in my next post, so don't look if you are trying it on your own!
\[(a-b)(a+b)=a^2-b^2\]in my example a=2x and b=3\[(2x-3)(2x+3)=(2x)^2-3^2=4x^2-9\]
can you try one more except let me put the answer down
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