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Mathematics 19 Online
OpenStudy (anonymous):

Help how can I add all the numbers from 1 to 100 without actually adding all of them one by one?!

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

by "all the numbers" you mean all the whole numbers right? \[1+2+3+...+98+99+100\]

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

there is a nice formula for this but we can see how it works by adding forwards and also backward

OpenStudy (anonymous):

\[1+2+3+...+98+99+100\] \[100+99+98+...+3+2+1\]

OpenStudy (anonymous):

you see that you will add to get \[101\] in each spot.

OpenStudy (anonymous):

what how does that help?

OpenStudy (anonymous):

oh you're right

OpenStudy (anonymous):

so that means there's a hundred '101s'

OpenStudy (anonymous):

THEN IT MUST BE 10100!

OpenStudy (anonymous):

exactly!

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

not 10100 because that is both of them together

OpenStudy (anonymous):

oh yea, so i have to divdie that by 2

OpenStudy (anonymous):

2 times your sum is 10100 so your sum is half of that

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

THANKS satellite73! you made it very clear!

OpenStudy (anonymous):

general formula is \[1+2+3+...+n=\frac{n(n+1)}{2}\]

OpenStudy (anonymous):

yw

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