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OpenStudy (anonymous):
Help how can I add all the numbers from 1 to 100 without actually adding all of them one by one?!
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OpenStudy (anonymous):
sure
OpenStudy (anonymous):
by "all the numbers" you mean all the whole numbers right?
\[1+2+3+...+98+99+100\]
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
there is a nice formula for this but we can see how it works by adding forwards and also backward
OpenStudy (anonymous):
\[1+2+3+...+98+99+100\]
\[100+99+98+...+3+2+1\]
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OpenStudy (anonymous):
you see that you will add to get
\[101\] in each spot.
OpenStudy (anonymous):
what how does that help?
OpenStudy (anonymous):
oh you're right
OpenStudy (anonymous):
so that means there's a hundred '101s'
OpenStudy (anonymous):
THEN IT MUST BE 10100!
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OpenStudy (anonymous):
exactly!
OpenStudy (anonymous):
oops
OpenStudy (anonymous):
thanks!
OpenStudy (anonymous):
not 10100 because that is both of them together
OpenStudy (anonymous):
oh yea, so i have to divdie that by 2
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OpenStudy (anonymous):
2 times your sum is 10100 so your sum is half of that
OpenStudy (anonymous):
got it
OpenStudy (anonymous):
THANKS satellite73! you made it very clear!
OpenStudy (anonymous):
general formula is
\[1+2+3+...+n=\frac{n(n+1)}{2}\]
OpenStudy (anonymous):
yw
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