What is the equation to the plane through P(4,-2,3) and parallel to 3x-7z=12

Question

anonymous · Answer

I guess just a quick run though of any ideas how to get there in english would help... Any help helps!

anonymous · Answer

I get the normal vector <3,0,7> and know it runs perpendicular to the plane...

anonymous · Answer

I can use the point to make a parametric equation...

x=4+3t
y=-2
z=3+7t

amistre64 · Answer

parallel to a y=0 plane eh ...

amistre64 · Answer

3x - 7z = 12

<3,0,-7> is the normal to this "plane" so its good for the normal for any plane parallel to it right?

amistre64 · Answer

given a normal and a point, all we do is put them together to get the plane equation.

3(x-4)+0(y--2)-7(z-3)=0

3x -12 -7z +21 = 0

3x -7z +9 = 0 should do it