Question

Solve the following equation:
(1/x)+2/(x-1)=3

Answer 1

cross multiply the left side of the equation.

Answer 2

\[x=\pm \sqrt{(6x-1)/3}\]

Answer 3

that will give you (x-1+2x)/(x^-x)

Answer 4

so that is incorrect

Answer 5

what I am saying is the first step to solving the equation.. I did not state the answer...

Answer 6

oh, is the answer correct

Answer 7

that is what you get from cross multiplication of the left side of your equation....

Answer 8

kumar hasnt been wrong yet.. i would bet he is right

Answer 9

i was just trying to teach you the problem..

Answer 10

x(x-1)1/x+x(x-1)2/x-1=x(x-1)3
(x-1)+2x=3x(x-1)
(x-1)+2x=3x^2-3x
3x-1=3x^2-3x

Answer 11

Correct, so far?

Answer 12

3x^2-3x-3x+1=0

Answer 13

3x^2-6x+1=0

Answer 14

how am I doing?

Answer 15

close..

Answer 16

step back to the beginning..

Answer 17

when you cross multiply.. leave the right side of the equation alone..

Answer 18

so just on the left side.. ( (x-1)(1) + 2(x) ) / (x * (x-1))

Answer 19

and that simplifies to (3x-1) / (x^2-x)

Answer 20

again... just on the left side

Answer 21

you with me?

Answer 22

yes

Answer 23

ok. now multiply both sides to get rid of the denominator on the left...

Answer 24

so you move the (x^-x) over

Answer 25

and get 3x-1 = 3x^ - 3x

Answer 26

so 3x-1=3x^2-3x

Answer 27

xactly.

Answer 28

thats what i had

Answer 29

now solve for x

Answer 30

3x^2-6x+1=0

Answer 31

quadratic equation...

Answer 32

i'm bad at factoring

Answer 33

i got +-sqrt(5)

Answer 34

shouldnt be any more factoring

Answer 35

oh

Answer 36

should be able to plug into the quadratic equation......

Answer 37

(-b+-sqrt(b^2-4ac)) / 2a

Answer 38

what is the step after 3x^2-6x+1=0

Answer 39

this...?
(-b+-sqrt(b^2-4ac)) / 2a