a particle moves along a circle of radius R=1 m so that its circumference rotates with constant angular velocity 2 rad/s. the linear speed of the particle is ?
\[v=r\omega\]\[v=1\times2\]\[v=2ms^{-1}\]
no thats absolutely wrong angular velocity about centre= 2(angular velocity about any point on its circumference) ω=2 (2) rad/s v = rω = 1(4) m/s
Angular velocity is the same at any radius, that's the point of it :)
no u cannot consider it like that
Why not?
angular velocity about centre is different from angular velocity about a point on circumference because the coordinates are going to change
I may have the wrong scenario here.|dw:1316678995512:dw|What I'm getting from the question is that the centre of the circle is stationary, and the circumference is rotating about the centre at an angular velocity of 2 rad/s due to a particle attached to it. You have to find the linear velocity of that particle. Is this the case?
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