Question

miker83 if you are on i figured it out

Answer 1

0=3t^2-12t+9 for some reason i wrote 2)
so yes v(t)=0 at t=1
V(t) shows the direction of the body
so pick points t=2 and t=0 and evaluate to figure out that it is postive in the 1st half and negative in the second

so in order to find the distance you must do it twice getting

(t(0)+t(1)) + |t(1)+t(2)

Answer 2

cross that last part you are finding the distance from 0 to 1 and the Absolute value of 1 to 2

Answer 3

my bad I'm guessing you are not on though

Answer 4

so basically the positive values of v(t) + the absolute values of the negative values of v(t)

Answer 5

if you were to draw this function it would be