5x2 + 3x – 2

FActor completely

Question

5x2 + 3x – 2

FActor completely

anonymous · Answer

5x^2

amistre64 · Answer

well, 5(2) = 10; and 5-2 = 3

anonymous · Answer

ok thats what i got, but whats the rule for the sign?

amistre64 · Answer

gotta love the moleasses lol

anonymous · Answer

(5x-2)(x+1)

anonymous · Answer

I was told to take the sign from the second term

amistre64 · Answer

the last sign tells us to add or subtract

the middle sign says the bigger factor is .... the middle sign

amistre64 · Answer

5 and 2; +5 and -2

amistre64 · Answer

(x+5/5)  (x-2/5) ; and reduce

(x+1) (x-2/5) ; if we got a fractions; stick the bottom in front

(x+1) (5x-2)

anonymous · Answer

oooohhh ok, I think i understand, hey can you help me with a few more, im honestly trying to gain a solid understanding

amistre64 · Answer

sure

anonymous · Answer

5x^2 + 40x + 80  
5/5   40/5    80/5
(x^2+8x+16)
       5 (x + 4)(x+4)

anonymous · Answer

first, 
Am i Correct here

amistre64 · Answer

that looks nice :)

anonymous · Answer

ok moving on

anonymous · Answer

5x^3 – 45xy^2

anonymous · Answer

the x and y threw me off :(

amistre64 · Answer

pull out the 5 first to clean it up

5(x^3 - 9x y^2)  ; now we see there is only an x in common
                                  so pull it out

5x(x^2 - 9y^2) ; and we see we are left with a diff of squares
                               so factor it :)

5x(x+3y)(x-3y)  and we are done

anonymous · Answer

You make it seem sooooooo easy lol, I suck at math

amistre64 · Answer

ive had lots or practice :)

anonymous · Answer

The next one is more of a expression type

anonymous · Answer

lol and i see ;)

anonymous · Answer

3x^3y^5z^2 – 9x^4y^6z^4 + 12x^2y^5z^3

anonymous · Answer

im trying to pull you the infomation i have from my lesson material

amistre64 · Answer

step one is always pull out common factors

$$\large 3x^3y^5z^2 – 9x^4y^6z^4 + 12x^2y^5z^3$$
i see a 3, and a few xyz s
$$\large 3x^2y^5z^2\ (x – 3x^2yz^2 + 4z)$$ the rest needs a good eye to see if its good to go

amistre64 · Answer

i think thats all we can do for it

anonymous · Answer

So is that the final answer

amistre64 · Answer

i believe so, but we can wolfram it to dbl chk; my eyes play tricks on me in my old age

anonymous · Answer

I see how you got it

amistre64 · Answer

http://www.wolframalpha.com/input/?i=factor+3x^3y^5z^2+%E2%80%93+9x^4y^6z^4+%2B+12x^2y^5z^3

amistre64 · Answer

wolf and i differ about the negation; but they are equivalent

anonymous · Answer

ok I see, thank you sooo much, this is very helpful

amistre64 · Answer

youre welcome; and good luck :)

anonymous · Answer

thanks again :)