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Evaluate the indefinite integral: 4xsin(x)dx
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i believe the easiest way is to use by parts
aka tabulars method, are you in calculus 2?
i got it down to -4xcos(x)+4cos(x) but i don't know if thats right
yeah calculus 2
i think the second should be a sin x
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-4xcos(x)+4sin(x)
thats right
\[\int\limits_{}^{}x \sin(x) dx=x \cdot( -\cos(x))-\int\limits_{}^{} 1 \cdot (-\cos(x)) dx=-x \cos(x)+\int\limits_{}^{}\cos(x) dx\] \[=-x \cos(x)+\sin(x)+C\] => \[4 \int\limits_{}^{} x \sin(x) dx=-4x \cos(x)+4 \sin(x)+K\]
I''ll show you tabulars in a drawing|dw:1316979579581:dw|
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