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How many total oxygens (O) are present on the reactant side of the equation. Al2O3 + 2NaOH + 3H2O ---> 2NaAl(OH)4
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there is eight oxygen atoms each side of the reaction
Al2O3 has 3 O 2NaOH has 2 O 3H2O has 3 O =8 O
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